Friday, October 10, 2014

An even more exact form of Stirling’s approximation is where higher-order terms inside the...

An even more exact form of Stirling’s approximation is where higher-order terms inside the parentheses are omitted. Take the natural logarithm of this expression and evaluate ln (5000!). Compare your answer with the value given in the table below equation 17.2. How close are the different values?

Equation 17.2

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